Question

value: 4
factor completely
$x^2 + 10x + 21$
\\(\circ\\) a. \\((x+3)(x+7)\\)
\\(\circ\\) b. \\((x+1)(x+21)\\)
\\(\circ\\) c. \\((x+4)(x+6)\\)
\\(\circ\\) d. \\((x+2)(x+8)\\)

Explanation:

Step1: Find pair summing to 10, product 21

[LLM SSE On Failure]

Answer:

a. (x+3)(x+7)