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Question
using the
as\ idea, how many electrons are \available\ for the compound sicl4? n = 40
Step1: Determine the number of valence electrons for each atom
- Silicon (\(Si\)) has \(4\) valence electrons.
- Chlorine (\(Cl\)) has \(7\) valence electrons.
Step2: Calculate the total number of available electrons
- There is \(1\) \(Si\) atom and \(4\) \(Cl\) atoms in \(SiCl_4\).
- Total valence electrons \(= (1\times4)+(4\times7)=4 + 28=32\)
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\(32\)