Question

use what you learned to solve these problems.
4 a dragonfish is swimming at -900 m relative to sea level. it rises 250 m. what is the dragonfish’s new depth relative to sea level? show your work.

Explanation:

Step1: Identify the initial depth and the change

The initial depth relative to sea level is -900 m (negative because it's below sea level). The dragonfish rises 250 m, which means we add 250 m to the initial depth.

Step2: Perform the calculation

To find the new depth, we calculate \(-900 + 250\). When adding a positive number to a negative number, we can think of it as subtracting the absolute value of the negative number's magnitude from the positive number's magnitude, but keeping the sign of the larger magnitude. Here, \(|-900| = 900\) and \(|250| = 250\), so we have \(900 - 250 = 650\), and since 900 is larger and negative, the result is \(-650\) m.

Answer:

The dragonfish's new depth relative to sea level is \(-650\) meters.