Question

use the references to access important values if needed for this question.
what volume of hydrogen gas is required to react with 74.5 liters of ethylene (c₂h₄) according to the following reaction? (all gases are at the same temperature and pressure.)
hydrogen (g) + ethylene (c₂h₄) (g) → ethane (c₂h₆) (g)
volume = l

Explanation:

Step1: Analyze the reaction equation

The reaction is \(H_2(g)+C_2H_4(g)\to C_2H_6(g)\). According to Avogadro's law, at the same temperature and pressure, the volume ratio of gases is equal to the mole ratio.

Step2: Determine the volume ratio

From the balanced chemical equation, the mole ratio of \(H_2\) to \(C_2H_4\) is \(1:1\). So the volume ratio of \(H_2\) to \(C_2H_4\) is also \(1:1\) at the same \(T\) and \(P\).

Step3: Calculate the volume of \(H_2\)

Given the volume of \(C_2H_4\) is \(V = 74.5\space L\). Since \(V(H_2):V(C_2H_4)=1:1\), then \(V(H_2)=74.5\space L\)

Answer:

\(74.5\space L\)