Question

use the partial quotients method to find 992 ÷ 32. fill in the missing numbers.

Explanation:

Step1: First partial - quotient

We know that \(320\div32 = 10\). So, the first number to fill in the box next to \(32\) for \(-320\) is \(10\). \(992-320 = 672\).

Step2: Second partial - quotient

Again, since \(320\div32 = 10\), the number in the box next to \(32\) for the second \(-320\) is \(10\). And \(672 - 320=352\).

Step3: Third partial - quotient

Since \(320\div32 = 10\), the number in the box next to \(32\) for the third \(-320\) is \(10\). And \(352 - 320 = 32\).

Step4: Fourth partial - quotient

Since \(32\div32=1\), the number in the box next to \(32\) for \(-32\) is \(1\).
The sum of the partial - quotients \(10 + 10+10 + 1=31\) and the remainder is \(0\).

Answer:

The quotient is \(31\) and the remainder is \(0\). The filled - in numbers from top to bottom, left to right are: \(31\), \(0\), \(10\), \(672\), \(10\), \(352\), \(10\), \(32\), \(1\), \(0\).