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use linear approximation, i.e. the tangent line, to approximate \\(\sqrt3{1.2}\\) as follows:
let \\(f(x) = \sqrt3{x}\\). the equation of the tangent line to \\(f(x)\\) at \\(x = 1\\) can be written in the form \\(y = mx + b\\)
where \\(m\\) is:
and where \\(b\\) is:
using this, we find our approximation for \\(\sqrt3{1.2}\\) is
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Use linear approximation, i.e. the tangent line, to approximate \(\sqrt[3]{1.2}\) as follows:
Let \(f(x) = \sqrt[3]{x}\). The equation of the tangent line to \(f(x)\) at \(x = 1\) can be written in the form \(y = mx + b\)
where \(m\) is: <blank>\(\frac{1}{3}\)</blank>
and where \(b\) is: <blank>\(\frac{2}{3}\)</blank>
Using this, we find our approximation for \(\sqrt[3]{1.2}\) is <blank>\(\frac{16}{15}\)</blank>