Question

use the image to complete the statements. the aluminum atom electrons to form an ion. the ion that is formed is

Explanation:

Aluminum has an atomic number of 13. Its electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\). In the outermost (valence) shell (the third shell here), it has 3 electrons. To achieve a stable electron configuration (a full outer shell, similar to the noble gas neon which has 8 electrons in its outer shell for the second - shell configuration, but for aluminum, losing 3 electrons will give it a stable \(2s^{2}2p^{6}\) configuration). When an atom loses electrons, it forms a positive ion (cation).

Answer:

The aluminum atom loses electrons to form an ion. The ion that is formed is \(Al^{3 +}\).