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Question
use the following information to answer the next question. the combustion reaction propene is shown below: $ach_3 - ch = ch_2 + bo_2 \to cco_2 + dh_2o$ the respective values of variables a, b, c and d are a) 2, 8, 5, 7 b) 3, 4, 3, 6 c) 3, 9, 9, 6 d) 2, 9, 6, 6 e) 2, 4, 6, 5
Step1: Balance the carbon atoms
The formula of propene is \(C_3H_6\). For carbon atoms: \(3a = c\).
Step2: Balance the hydrogen atoms
For hydrogen atoms: \(6a=2d\), so \(d = 3a\).
Step3: Balance the oxygen atoms
For oxygen atoms: \(2b=2c + d\). Substitute \(c = 3a\) and \(d = 3a\) into \(2b=2c + d\), we get \(2b=2\times3a+3a=9a\).
Now let's check each option:
- Option a: If \(a = 2\), \(c=3a = 6
eq5\), so this option is wrong.
- Option b: If \(a = 3\), \(d=3a = 9
eq6\), so this option is wrong.
- Option c: If \(a = 3\), \(d=3a = 9
eq6\), so this option is wrong.
- Option d: If \(a = 2\), \(c = 3a=6\), \(d = 3a = 6\), and \(b=\frac{9a}{2}=\frac{9\times2}{2}=9\). This option satisfies the balance of \(C\), \(H\), and \(O\) atoms.
- Option e: If \(a = 2\), \(d=3a = 6
eq5\), so this option is wrong.
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D. 2, 9, 6, 6