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use the following diagram to prove the perpendicular bisector theorem. …

Question

use the following diagram to prove the perpendicular bisector theorem.
given: \\( \overline { c d } \\) is the perpendicular bisector of \\( \overline { a b } \\).
prove: \\( \overline { a d } \cong \overline { b d } \\)
\\( \overline { c d } \\) is the perpendicular bisector of \\( \overline { a b } \\).
\\( \overline { a c } \cong \overline { b c } \\)
\\( m \angle a c d = 90 ^ { \circ }, m \angle b c d = 90 ^ { \circ } \\)
\\( \overline { c d } \cong \overline { c d } \\)
\\( \delta a c d \cong \delta b c d \\)

Explanation:

Step1: Fill in the first blank

The first statement is given, so the reason is "Given".

Step2: Second statement

Since \(CD\) is the perpendicular bisector of \(AB\), by the definition of a perpendicular bisector, \(C\) is the mid - point of \(AB\). So the statement is "\(\overline{AC}\cong\overline{BC}\)" (mid - point property) and the reason for the second blank (the statement "\(\overline{AC}\cong\overline{BC}\)") is "Definition of a bisector".

Step3: Third statement

The angles \(\angle ACD\) and \(\angle BCD\) are right angles. The reason for \(m\angle ACD = 90^{\circ},m\angle BCD=90^{\circ}\) is "Definition of perpendicular lines" (because \(CD\perp AB\)).

Step4: Fourth statement

Since \(\angle ACD\) and \(\angle BCD\) are right angles, \(\angle ACD\cong\angle BCD\) (all right angles are congruent).

Step5: Fifth statement

For \(\triangle ACD\) and \(\triangle BCD\), we have \(\overline{AC}\cong\overline{BC}\), \(\angle ACD\cong\angle BCD\), and \(\overline{CD}\cong\overline{CD}\) (reflexive property). By the Side - Angle - Side (SAS) congruence criterion, \(\triangle ACD\cong\triangle BCD\).

Step6: Sixth statement

Since \(\triangle ACD\cong\triangle BCD\), by the Corresponding Parts of Congruent Triangles are Congruent (CPCTC) theorem, \(\overline{AD}\cong\overline{BD}\).

Answer:

StatementsReasons
\(\overline{AC}\cong\overline{BC}\)Definition of a bisector
\(m\angle ACD = 90^{\circ},m\angle BCD = 90^{\circ}\)Definition of perpendicular lines
\(\angle ACD\cong\angle BCD\)All right angles are congruent
\(\overline{CD}\cong\overline{CD}\)Reflexive property
\(\triangle ACD\cong\triangle BCD\)SAS congruence criterion
\(\overline{AD}\cong\overline{BD}\)CPCTC