Question

unit 6 sol review

1. line l1 has the following equation: 3x - 6y = -36

2a express the equation of l1 in slope-intercept form.
enter your next step here

Explanation:

Step1: Recall slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. We need to solve the given equation $3x-6y=-36$ for $y$.

Step2: Isolate the $y$ - term

Subtract $3x$ from both sides of the equation:
$-6y=-3x - 36$

Step3: Solve for $y$

Divide each term in the equation $-6y=-3x - 36$ by $-6$:
$y=\frac{-3x}{-6}+\frac{-36}{-6}$

Simplify the fractions:
$y=\frac{1}{2}x + 6$

Answer:

$y=\frac{1}{2}x + 6$