Question

unit: functions
progress:
the movement of the progress bar may be uneven because questions can be worth more or l
find the domain of $f(x) = -\sqrt{x^2 - 16}$.
\\( x \geq 4 \\)
\\( x \geq 4 \\) or \\( x \leq -4 \\)
\\( x \geq -4 \\) or \\( x \leq 4 \\)
all real numbers

Explanation:

Step1: Set radicand non-negative

\( x^2 - 16 \geq 0 \)

Step2: Solve quadratic inequality

\( x^2 \geq 16 \) → \( |x| \geq 4 \) → \( x \geq 4 \) or \( x \leq -4 \)

Answer:

B. \( x \geq 4 \) or \( x \leq -4 \)