Question

unit factoring progress: the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. factor the expression by grouping: $2x^2 + 6x - 5x - 15$ $\circ$ $(2x - 5)(x + 3)$ $\circ$ $(2x - 3)(x + 5)$ $\circ$ $(2x + 3)(x - 5)$ $\circ$ $(2x + 5)(x - 9)$

Explanation:

Step1: Group the terms

Group the first two and last two terms: \( (2x^2 + 6x) + (-5x - 15) \)

Step2: Factor out GCF from each group

Factor \( 2x \) from first group: \( 2x(x + 3) \)
Factor \( -5 \) from second group: \( -5(x + 3) \)
Now we have \( 2x(x + 3) - 5(x + 3) \)

Step3: Factor out common binomial

Factor out \( (x + 3) \): \( (2x - 5)(x + 3) \)

Answer:

\( (2x - 5)(x + 3) \) (the first option among the given choices)