Question

unit 1: algebra basics
bell: _
homework 11: solving & graphing inequalities

1. ( \frac { x } { 3 } + 10 geq 15 )

Explanation:

Step1: Subtract 10 from both sides

$$\frac{x}{3}+10 - 10\geq15 - 10$$
$$\frac{x}{3}\geq5$$

Step2: Multiply both sides by 3

$$\frac{x}{3}\times3\geq5\times3$$
$$x\geq15$$

Answer:

The solution of the inequality is \(x\geq15\). On the number - line, we draw a closed circle at \(x = 15\) (because the inequality includes equality, i.e., \(x\) can be equal to 15) and draw an arrow to the right (since \(x\) is greater than or equal to 15).