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understanding key ideas 2. boyle’s law describes the relationship betwe…

Question

understanding key ideas

  1. boyle’s law describes the

relationship between
a. volume and pressure.
b. temperature and pressure.
c. temperature and volume.
d. all of the above

  1. what are the effects of a warm

temperature on gas particles?
math skills

  1. you have 3 l of gas at a certain

temperature and pressure. what
would the volume of the gas be
if the temperature doubled and
the pressure stayed the same?

Explanation:

Response
Question 2
Brief Explanations

Boyle’s Law states that for a fixed amount of gas at constant temperature, the pressure and volume are inversely proportional. So it describes the relationship between volume and pressure. Option b is about Gay - Lussac's Law (pressure - temperature at constant volume), option c is about Charles's Law (volume - temperature at constant pressure), and option d is incorrect as Boyle's Law only relates volume and pressure.

Brief Explanations

According to the kinetic theory of gases, when the temperature of a gas is warm (increased), the average kinetic energy of the gas particles increases. This means the gas particles move faster, collide more frequently with each other and the container walls, and have greater force in their collisions.

Step1: Recall Charles's Law

Charles's Law states that for a fixed amount of gas at constant pressure, the volume of a gas is directly proportional to its absolute temperature. The formula is $\frac{V_1}{T_1}=\frac{V_2}{T_2}$, where $V_1$ is the initial volume, $T_1$ is the initial temperature, $V_2$ is the final volume, and $T_2$ is the final temperature.

Step2: Substitute the given values

We know that $V_1 = 3\space L$, and $T_2 = 2T_1$ (temperature doubled) and pressure is constant. Substituting into Charles's Law formula: $\frac{3}{T_1}=\frac{V_2}{2T_1}$.

Step3: Solve for $V_2$

Cross - multiply: $V_2\times T_1=3\times2T_1$. Then divide both sides by $T_1$ (since $T_1
eq0$), we get $V_2 = 6\space L$.

Answer:

a. volume and pressure.

Question 3