Question

in the typical divide - and - conquer case, what size are the subproblems divided into?
select one
a. about half the original problems size.
b. none of these.
c. proportional to the original problems size.
d. twice the original problems size.

Explanation:

In a typical divide - and - conquer algorithm, the problem is divided into sub - problems. The most common approach is to divide the problem into sub - problems of approximately half the size of the original problem. For example, in merge sort, the array is divided into two sub - arrays of roughly half the size each. Option A is correct as it aligns with the common practice in divide - and - conquer algorithms. Option C is incorrect because "proportional" is too vague and not the typical description. Option D is incorrect as making sub - problems twice the size would not be a "divide" step in the context of divide - and - conquer.

Answer:

A. About half the original problem's size.