4) type of reaction: combustion ch4 + o2 → co2 + h2o 5) type of reaction: synthesis h2o + so3 → h2so4

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Accepted Answer

# Explanation:
## Step1: Balance carbon atoms
In $CH_4 + O_2
ightarrow CO_2 + H_2O$, there is 1 carbon atom on the left (in $CH_4$) and 1 carbon atom on the right (in $CO_2$). So the coefficient of $CH_4$ and $CO_2$ is 1.
## Step2: Balance hydrogen atoms
There are 4 hydrogen atoms in $CH_4$. In $H_2O$, each molecule has 2 hydrogen atoms. So to balance hydrogen, the coefficient of $H_2O$ is 2 ($2\times2 = 4$).
## Step3: Balance oxygen atoms
On the right - hand side, there are $2 + 2=4$ oxygen atoms (2 from $CO_2$ and 2 from $2H_2O$). In $O_2$, each molecule has 2 oxygen atoms. So the coefficient of $O_2$ is 2 ($2\times2 = 4$).

For $H_2O+SO_3
ightarrow H_2SO_4$:
## Step1: Count atoms
On the left - hand side, there are 2 H, 1 + 3 = 4 O, and 1 S. On the right - hand side, in $H_2SO_4$, there are 2 H, 4 O, and 1 S. So the coefficients of $H_2O$, $SO_3$, and $H_2SO_4$ are all 1.

# Answer:
For $CH_4+\underline{2}O_2
ightarrow\underline{1}CO_2+\underline{2}H_2O$ and for $H_2O+\underline{1}SO_3
ightarrow\underline{1}H_2SO_4$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance carbon atoms

Step2: Balance hydrogen atoms

Step3: Balance oxygen atoms

Step1: Count atoms

Answer: