Question

type the numbers that will balance this equation.
if no number is required type a 1 in that blank.

c₃h₈ (l) + o₂ (g) -----> co₂ (g) + h₂o (l)

Explanation:

Step1: Balance carbon atoms

For \(C_3H_8\), there are 3 carbon atoms. So, the coefficient of \(CO_2\) should be 3.
$$C_3H_8(l)+O_2(g)\to3CO_2(g)+H_2O(l)$$

Step2: Balance hydrogen atoms

In \(C_3H_8\), there are 8 hydrogen atoms. So, the coefficient of \(H_2O\) should be 4.
$$C_3H_8(l)+O_2(g)\to3CO_2(g)+4H_2O(l)$$

Step3: Balance oxygen atoms

On the right - hand side, the number of oxygen atoms in \(3CO_2\) is \(3\times2 = 6\) and in \(4H_2O\) is 4. So, the total number of oxygen atoms on the right - hand side is \(6 + 4=10\). Then the coefficient of \(O_2\) should be 5.
$$C_3H_8(l)+5O_2(g)\to3CO_2(g)+4H_2O(l)$$

Answer:

1, 5, 3, 4