Question

two ordered pairs that are 3.5 units apart. distance = 3.5 units (-0.5,-1.5) (3.5,5.5) (-0.5,2) (-3,2) (3.5,-1) two ordered pairs. -0.5,2) -3,2) -0.5,-1.5)

Explanation:

Step1: Use the distance formula for points with same \(x\) - coordinate

The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). If \(x_1=x_2\), then \(d=\vert y_2 - y_1\vert\).
For the points \((- 0.5,-1.5)\) and \((-0.5,2)\), \(x_1=-0.5,x_2=-0.5,y_1=-1.5,y_2 = 2\).

Step2: Calculate the distance

Substitute into \(d=\vert y_2 - y_1\vert\). We get \(d=\vert2-(-1.5)\vert=\vert2 + 1.5\vert=\vert3.5\vert = 3.5\)

Answer:

The ordered pairs \((-0.5,-1.5)\) and \((-0.5,2)\) are \(3.5\) units apart.