Question

two miscible liquids were mixed to the point of saturation. it was found that there was 25.00 ml of liquid a in every 350.00 ml of the solution.

1. what is the % v/v?

1 ml a
% v/v = ---------------- 100% = 2 %
3 ml soln

1. how many ml of liquid a are in 25.00 ml of the solution ? (dont use % here, use actual numbers)

4 ml a
(5 ml soln)(----------------) = 6 ml a
7 ml soln
a. 36.00 b. 5.00 c. 31.00 d. 150.0 e. 12 f. 350.00
g. 100.0 h. 2.4 x 10^{-2} i. 1.2 x 10^{-3} j. 1.786 k. 7.143 l. 25.00
m. 7.500 n. 125.0 o. 500.0 p. 15.00 q. 185.00 r. 444.44
s. 2.00 x 10^{3} t. 20.67 u. 0.500 v. 499.5 w. 15 x. 33.33
y. 1.00 x 10^{5} z. 10.0 aa. 1.00 bb. 10^{6} cc. 6.00
dd. 6.00 x 10^{-5} ee. 6.00 x 10^{6} ff. 20.0 gg. 200 hh. 1.20 x 10^{6}
ii. 60 jj. 0.100 kk. 4.00 ll. 10^{3} mm. 0.0667 nn. 66.7

Explanation:

Step1: Calculate \(\%v/v\)

The formula for \(\%v/v=\frac{\text{Volume of solute (A)}}{\text{Volume of solution}}\times100\%\). Here, volume of solute (A) \(V_A = 25.00\) mL and volume of solution \(V_{soln}=350.00\) mL.
So, \(\%v/v=\frac{25.00}{350.00}\times100\%\)

$$=\frac{2500}{350.00}\%=\frac{250}{35}\%=\frac{50}{7}\%\approx7.143\%$$

Step2: Calculate volume of A in \(25.00\) mL solution

Let \(x\) be the volume of A in \(25.00\) mL solution. Using the ratio from \(\%v/v\), we have \(\frac{V_A}{V_{soln}}=\frac{x}{25.00}\). Since \(\frac{V_A}{V_{soln}}=\frac{25.00}{350.00}\), then \(x=(25.00)\times\frac{25.00}{350.00}\)

$$x=\frac{625}{350}\text{mL}\approx1.786\text{mL}$$

Answer:

1. \(1 = 25.00\), \(2 = 7.143\), \(3 = 350.00\)
2. \(4 = 25.00\), \(5 = 25.00\), \(6 = 1.786\), \(7 = 350.00\)