Question

if ∠tuv and ∠pqr are a linear pair, and m∠tuv is equal to 88°, then what is m∠pqr? m∠pqr = ?°

Explanation:

Step1: Recall the property of linear pair

A linear pair of angles is supplementary, i.e., their sum is \(180^{\circ}\). So, \(m\angle TUV + m\angle PQR=180^{\circ}\).

Step2: Substitute the given value

Given \(m\angle TUV = 88^{\circ}\), substitute into the equation: \(88^{\circ}+m\angle PQR = 180^{\circ}\).

Step3: Solve for \(m\angle PQR\)

Subtract \(88^{\circ}\) from both sides: \(m\angle PQR=180^{\circ}- 88^{\circ}\).

$$m\angle PQR = 92^{\circ}$$

Answer:

\(92\)