Question

a truck with a mass of 870 kg increases its speed from 20 m/s to 32 m/s in 16 s. how much force did it take to complete this action?

Explanation:

Step1: Calculate acceleration

Use the formula \(a=\frac{v - u}{t}\), where \(v = 32\ m/s\), \(u = 20\ m/s\), \(t = 16\ s\).
\(a=\frac{32 - 20}{16}=\frac{12}{16}= 0.75\ m/s^{2}\)

Step2: Calculate force

Use Newton's second law \(F = ma\), where \(m = 870\ kg\), \(a=0.75\ m/s^{2}\).
\(F=870\times0.75 = 652.5\ N\)

Answer:

\(652.5\ N\)