Question

6.4 trinomials where a doe
(1 point)
factor:
$6x^2 - 25x - 25 = \square$
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Explanation:

Step1: Find product of a and c

$a=6, c=-25$, so $6×(-25)=-150$

Step2: Find factor pair of -150

Find two numbers: product=-150, sum=-25 → -30 and 5

Step3: Split middle term

$6z^2 -30z +5z -25$

Step4: Factor by grouping

$6z(z-5)+5(z-5)=(6z+5)(z-5)$

Answer:

$(6z + 5)(z - 5)$