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triangle stu is formed by connecting the midpoints of the side of trian…

Question

triangle stu is formed by connecting the midpoints of the side of triangle pqr. the measures of the interior angles of triangle pqr are shown. find the measure of ∠qst. figures not necessarily drawn to scale.

Explanation:

Step1: Find ∠PRQ (wait, no, first find ∠PQR? Wait, triangle PQR has angles at R: 54°, at Q: 82°, at P: 44°? Wait, sum of angles in triangle is 180°. Wait, S is midpoint? Wait, STU is formed by midpoints, so ST is midline? Wait, no, first, let's recall that in triangle PQR, angles are ∠R = 54°, ∠Q = 82°, ∠P = 44° (since 54 + 82 + 44 = 180). Now, S is midpoint of PQ? Wait, no, the problem says STU is formed by connecting midpoints of PQR. So S, T, U are midpoints. So ST is parallel to PR? Wait, no, midline theorem: the segment connecting midpoints of two sides is parallel to the third side and half its length. So if S is midpoint of PQ, T is midpoint of QR, then ST || PR and ST = ½ PR. Then ∠QST would be equal to ∠QPR (corresponding angles) because ST || PR. Wait, ∠QPR is ∠P, which is 44°? Wait, no, wait: ∠QST and ∠QPR: if ST || PR, then ∠QST = ∠QPR (corresponding angles). Wait, but let's check the angles. Wait, triangle PQR: angles at R: 54°, Q: 82°, so angle at P is 180 - 54 - 82 = 44°. Now, S is midpoint of PQ? Wait, no, S is on PQ? Wait, the diagram: S is on PQ, T is on QR, U is on PR? Wait, maybe ST is parallel to PR. So ∠QST = ∠QPR (since ST || PR, corresponding angles). So ∠QST = 44°? Wait, no, wait: angle at P is 44°, so if ST is parallel to PR, then ∠QST = ∠QPR = 44°? Wait, no, maybe I got the sides wrong. Wait, let's re-examine. The triangle PQR: vertices P, Q, R. S is on PQ, T is on QR, U is on PR. Then ST connects midpoints of PQ and QR? No, midpoints: so S is midpoint of PQ, T is midpoint of QR, U is midpoint of PR. Then ST is midline, so ST || PR, and ∠QST = ∠QPR (corresponding angles). So ∠QPR is 44°, so ∠QST = 44°? Wait, but let's confirm. Alternatively, maybe S is midpoint of PQ, so QS = SP. But the key is that ST is midline, so parallel to PR, so ∠QST = ∠QPR (since ST || PR, transversal QP). So ∠QPR is 44°, so ∠QST is 44°? Wait, but let's check the angle sum. 54 (∠R) + 82 (∠Q) + 44 (∠P) = 180, correct. So ∠QST = ∠P = 44°? Wait, no, wait: if ST is parallel to PR, then ∠QST and ∠QPR are corresponding angles, so they should be equal. So ∠QST = 44°. Wait, but maybe I made a mistake. Wait, another approach: since S and T are midpoints, ST is midline, so ST || PR, so ∠QST = ∠QPR (corresponding angles). ∠QPR is 44°, so ∠QST is 44°.

Step2: Confirm angle sum. In triangle PQR, angles are 54 (R), 82 (Q), 44 (P). Sum is 54+82=136, 180-136=44. Correct. Then ST || PR, so corresponding angles ∠QST and ∠QPR are equal. So ∠QST = 44°.

Answer:

44°