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Question
triangle pqr has vertices p(-2,6), q(-8,4), and r(1,-2). it is translated according to the rule (x,y)→(x - 2,y - 16). what is the y - value of p? -18 -16 -12 -10
Step1: Identify the y - coordinate of point P
The coordinates of point P are \((-2,6)\). The y - coordinate of point P is \(y = 6\).
Step2: Apply the translation rule to the y - coordinate
The translation rule is \((x,y)\to(x - 2,y-16)\). For the y - coordinate, we use the formula \(y'=y - 16\).
Substitute \(y = 6\) into the formula: \(y'=6-16\).
Calculate \(6-16=-10\).
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- 10 (the fourth option)