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Question
triangle pqr has vertices \\(p(-2, 6)\\), \\(q(-8, 4)\\), and \\(r(1, -2)\\). it is translated according to the rule \\((x, y) \
ightarrow (x - 2, y - 16)\\).
what is the y-value of p?
-18
-16
-12
-10
Identify the initial coordinates of point P
$$
P = (-2, 6) \implies y = 6
$$
Apply the translation rule to the y-coordinate
$$
y' = y - 16
$$
Calculate the final y-value
$$
y' = 6 - 16 = -10
$$
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- (A) \(-18\)
- (B) \(-16\)
- (C) \(-12\)
- (D) \(-10\) (Correct answer)