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triangle pqr has vertices \\(p(-2, 6)\\), \\(q(-8, 4)\\), and \\(r(1, -…

Question

triangle pqr has vertices \\(p(-2, 6)\\), \\(q(-8, 4)\\), and \\(r(1, -2)\\). it is translated according to the rule \\((x, y) \
ightarrow (x - 2, y - 16)\\).

what is the y-value of p?

-18
-16
-12
-10

Explanation:

Identify the initial coordinates of point P

$$ P = (-2, 6) \implies y = 6 $$

Apply the translation rule to the y-coordinate

$$ y' = y - 16 $$

Calculate the final y-value

$$ y' = 6 - 16 = -10 $$

Answer:

  • (A) \(-18\)
  • (B) \(-16\)
  • (C) \(-12\)
  • (D) \(-10\) (Correct answer)