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the triangle below is isosceles. find the value of y. y = ? (y + 16)° 5…

Question

the triangle below is isosceles. find the value of y. y = ? (y + 16)° 51°

Explanation:

Step1: Recall angle - sum property of a triangle

The sum of the interior angles of a triangle is 180°. In an isosceles triangle, two angles are equal. Here, we assume the two given non - right angles are equal, so we have the equation $(y + 16)+51+(y + 16)=180$.

Step2: Simplify the left - hand side of the equation

Combine like terms: $2(y + 16)+51=180$. First, expand $2(y + 16)$ to get $2y+32$. Then the equation becomes $2y+32 + 51=180$, which simplifies to $2y+83 = 180$.

Step3: Isolate the variable y

Subtract 83 from both sides of the equation: $2y=180 - 83$, so $2y=97$. Then divide both sides by 2: $y=\frac{97}{2}=48.5$.

Answer:

$48.5$