Question

1
trial 1
cm
trial 2
cm
trial 3
cm
avg. dist.
cm
scenario
different person
with no warning
20.00
21.00
18.00
19.60
different person
with warning
30.00
27.00
18.00
25.00
same person
14.00
14.00
16.00
33.00
have the same person perform the experiment or have different pe

Explanation:

To find the correct average distance for the "Same person" scenario, we calculate the average of the three trials.

Step 1: Sum the trial distances

The distances for the three trials are \( 14.00 \, \text{cm} \), \( 14.00 \, \text{cm} \), and \( 16.00 \, \text{cm} \).
The sum is \( 14.00 + 14.00 + 16.00 = 44.00 \, \text{cm} \).

Step 2: Divide by the number of trials

There are 3 trials, so the average is \( \frac{44.00}{3} \approx 14.67 \, \text{cm} \) (rounded to two decimal places).

The correct average distance for the "Same person" scenario is approximately \( \boldsymbol{14.67} \, \text{cm} \) (replacing the incorrect \( 33.00 \, \text{cm} \) in the table).

Answer:

To find the correct average distance for the "Same person" scenario, we calculate the average of the three trials.

Step 1: Sum the trial distances

The distances for the three trials are \( 14.00 \, \text{cm} \), \( 14.00 \, \text{cm} \), and \( 16.00 \, \text{cm} \).
The sum is \( 14.00 + 14.00 + 16.00 = 44.00 \, \text{cm} \).

Step 2: Divide by the number of trials

There are 3 trials, so the average is \( \frac{44.00}{3} \approx 14.67 \, \text{cm} \) (rounded to two decimal places).

The correct average distance for the "Same person" scenario is approximately \( \boldsymbol{14.67} \, \text{cm} \) (replacing the incorrect \( 33.00 \, \text{cm} \) in the table).