Question

total distance travelled

1. a quarterback back pedals 2.2 meters southward and then runs 6.8 meters northward.
2. direction distance (m)

qb moves south
qb moves north
total distance travelled
direction displacement of each motion (m)
qb moves south
qb moves north
displacement of qb

Explanation:

Step1: Fill in distance values

The quarterback moves 2.2 meters south and 6.8 meters north. So for the "QB moves south" row in the distance - table, the distance is 2.2 m, and for the "QB moves north" row, the distance is 6.8 m. The total distance travelled is the sum of the distances of each motion, so $2.2 + 6.8=9$ m.

Step2: Determine displacement values

Displacement is a vector - quantity. Let the south - direction be negative and the north - direction be positive. The displacement of the south - ward motion is - 2.2 m and the displacement of the north - ward motion is + 6.8 m. The net displacement of the quarterback is $-2.2+6.8 = 4.6$ m (northward).

Direction	Distance (m)
QB moves north	6.8
Total distance travelled	9

Direction	Displacement of each motion (m)
QB moves north	6.8
Displacement of QB	4.6 (northward)

Answer:

Direction	Distance (m)
QB moves north	6.8
Total distance travelled	9

Direction	Displacement of each motion (m)
QB moves north	6.8
Displacement of QB	4.6 (northward)