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topic 3: factoring polynomials 17. $20x^2y - 28x$

Question

topic 3: factoring polynomials

  1. $20x^2y - 28x$

Explanation:

Step1: Find GCF of coefficients and variables

The coefficients are 20 and 28. GCF of 20 and 28 is 4. For variables, the common variable is \( x \) (with lowest power 1). So GCF is \( 4x \).

Step2: Factor out GCF from the polynomial

Divide each term by \( 4x \): \( \frac{20x^3y}{4x} = 5x^2y \), \( \frac{-28x}{4x} = -7 \). So factored form is \( 4x(5x^2y - 7) \).

Answer:

\( 4x(5x^2y - 7) \)