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b.e.s.t test prep what is the solution of the system of linear equation…

Question

b.e.s.t test prep what is the solution of the system of linear equations?
y = 3x - 4
y = -2x + 6
a. (1, -1)
b. (1, -4)
c. (2, -2)
d. (2, 2)

Explanation:

Step1: Set equations equal

Since \( y = 3x - 4 \) and \( y = -2x + 6 \), set \( 3x - 4 = -2x + 6 \).

Step2: Solve for x

Add \( 2x \) to both sides: \( 5x - 4 = 6 \). Add 4 to both sides: \( 5x = 10 \). Divide by 5: \( x = 2 \).

Step3: Find y

Substitute \( x = 2 \) into \( y = 3x - 4 \): \( y = 3(2) - 4 = 6 - 4 = 2 \). So the solution is \( (2, 2) \).

Answer:

D. (2, 2)