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question 1
what is the mass of a $2.16 \times 10^{-4} \\, \text{m}^3$ sample of mercury? refer to table 11.1.
0.0343 kg
0.002 94 kg
2.94 kg
6.29 kg

Explanation:

Step1: Recall density formula

Density $
ho = \frac{m}{V}$, so $m =
ho V$. Mercury's density (from standard tables) is $13593 \, \text{kg/m}^3$.

Step2: Calculate mass

Substitute values: $m = (13593) \times (2.16 \times 10^{-4})$.

Step3: Compute result

$13593 \times 2.16 \times 10^{-4} \approx 2.94 \, \text{kg}$.

Answer:

2.94 kg