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question 8
a bat strikes a 0.050 - kg baseball so that its velocity changes by + 32 m/s in 0.080 s. with what average force was the ball struck?
+ 20 n

• 200 n

+ 10 n

• 20 n

+ 200 n

Explanation:

Step1: Recall the formula for force

According to Newton's second law, \(F = ma\), and acceleration \(a=\frac{\Delta v}{\Delta t}\). So \(F = m\frac{\Delta v}{\Delta t}\).

Step2: Substitute the given values

Given \(m = 0.050\space kg\), \(\Delta v=+ 32\space m/s\), \(\Delta t = 0.080\space s\).
Substitute into the formula: \(F=(0.050)\times\frac{32}{0.080}\).
First calculate \(\frac{32}{0.080}=400\).
Then \(F = 0.050\times400=20\space N\).

Answer:

+20 N