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an engineer is asked to design a playground slide such that the speed a child reaches at the bottom does not exceed 6.0 m/s. determine the maximum height that the slide can be. friction is negligible.
2.9 m
3.2 m
7.4 m
1.8 m
4.5 m
Step1: Apply conservation of mechanical energy
Since friction is negligible, the potential energy at the top \(mgh\) is converted to kinetic energy at the bottom \(\frac{1}{2}mv^{2}\). So, \(mgh=\frac{1}{2}mv^{2}\).
Step2: Solve for height \(h\)
Cancel out the mass \(m\) from both sides of the equation \(mgh=\frac{1}{2}mv^{2}\). We get \(h = \frac{v^{2}}{2g}\). Given \(v = 6.0\ m/s\) and \(g=9.8\ m/s^{2}\), then \(h=\frac{6.0^{2}}{2\times9.8}=\frac{36}{19.6}\approx1.8\ m\)
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1.8 m