Question

1. tank a has a capacity of 9.5 gallons. $6\frac{1}{3}$ gallons of the tank’s water are poured out. how many gallons of water are left in the tank?

Explanation:

Step1: Convert 9.5 to fraction

9.5 can be written as a fraction. Since 0.5 is $\frac{1}{2}$, 9.5 is $9\frac{1}{2}$ or $\frac{19}{2}$.

Step2: Subtract the poured - out amount from the total capacity

We need to calculate $\frac{19}{2}-6\frac{1}{3}$. First, convert $6\frac{1}{3}$ to an improper fraction, which is $\frac{19}{3}$. Then find a common denominator for $\frac{19}{2}$ and $\frac{19}{3}$. The common denominator of 2 and 3 is 6. So $\frac{19}{2}=\frac{19\times3}{2\times3}=\frac{57}{6}$ and $\frac{19}{3}=\frac{19\times2}{3\times2}=\frac{38}{6}$. Now subtract: $\frac{57}{6}-\frac{38}{6}=\frac{57 - 38}{6}=\frac{19}{6}$. Convert $\frac{19}{6}$ to a mixed number, which is $3\frac{1}{6}\approx3.1667$.

Answer:

$3\frac{1}{6}$ (or approximately 3.17) gallons