Question

tanθ = adjacent/opposite opposite/adjacent hypotenuse/adjacent opposite/hypotenuse

Explanation:

Step1: Recall trigonometric ratio definitions

In a right - triangle, for an acute angle \(\theta\), \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\), \(\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}\), and \(\tan\theta=\frac{\text{opposite}}{\text{adjacent}}\).

Answer:

\(\frac{\text{opposite}}{\text{adjacent}}\) (the second option: \(\frac{\text{opposite}}{\text{adjacent}}\))