QUESTION IMAGE
Question
the table shows the amount of money, a, in a savings account after n months. select all the equations that represent the relationship between the amount of money, a, and the number of months, n.
| number of months | dollar amount |
|---|---|
| 6 | 1,300 |
| 7 | 1,400 |
| 8 | 1,500 |
a. a = 100n
b. a = 100(n - 5)
c. a - 700 = 100n
d. a - 1,200 = 100n
e. a = 700 + 100n
f. a = 1200 + 100n
g. a = 1,200 + 100(n - 5)
Step1: Find the rate of change
The change in amount $\Delta A=1300 - 1200=100$ when the change in months $\Delta m = 6 - 5=1$. The rate of change (slope) is $\frac{\Delta A}{\Delta m}=100$.
Step2: Use the point - slope form
We can use the point - slope form of a linear equation $y - y_1=m(x - x_1)$. Using the point $(m_1,A_1)=(5,1200)$ and slope $m = 100$, we get $A-1200 = 100(m - 5)$. Simplifying gives $A=1200+100(m - 5)$.
We can also find the $y$-intercept form. Let $A=bm + c$. Substituting $m = 5,A = 1200$ and $b = 100$ into $A=bm + c$, we have $1200=100\times5 + c$. Solving for $c$: $c=1200 - 500=700$. So the equation is $A=700 + 100m$.
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E. $A = 700+100m$, G. $A = 1200+100(m - 5)$