Question

svlc algebra 1a - standard (15260)
literal equations
solving a literal equation
solve for f: 6f + 9g = 3g + f
options:
$f = \frac{-9y}{3}$ (note: likely typo, should be $g$)
$f = \frac{-6g}{5}$
$f = \frac{12g}{7}$
$f = \frac{-9g}{6}$

Explanation:

Step1: Isolate terms with f

Subtract \( f \) and \( 9g \) from both sides: \( 6f - f = 3g - 9g \)

Step2: Simplify both sides

Left: \( 5f \), Right: \( -6g \)

Step3: Solve for f

Divide by 5: \( f = \frac{-6g}{5} \)

Answer:

\( f = \frac{-6g}{5} \) (corresponding to the option \( f = \frac{-6g}{5} \))