QUESTION IMAGE
Question
- suppose \\( \triangle rst \\) is translated and then reflected to form \\( \triangle r ^ { prime } s ^ { prime } t ^ { prime } \\). select all of the statements that are true.
a. length \\( overline { r ^ { prime } s ^ { prime } } = 4.3 \mathrm { cm } \\)
b. \\( \angle r \cong \angle r ^ { prime } \\)
c. \\( m \angle t ^ { prime } = 71 \\)
d. \\( overline { s t } \cong overline { t ^ { prime } s ^ { prime } } \\)
e. length \\( overline { r t } > \\) length \\( overline { r ^ { prime } t ^ { prime } } \\)
- point \\( t \\) is at \\( ( - 2,5 ) \\). what are the coordinates of point \\( t ^ { prime } \\) after a reflection across \\( x = 0 \\) and then \\( y = 0 ? ( , ) \\)
- \\( overline { p q } \\) is reflected across the line \\( x = - 1 \\). select all that apply.
a. \\( overline { p q } \cong overline { p ^ { prime } q ^ { prime } } \\)
b. \\( q ^ { prime } \\) is plotted at \\( ( - 4,4 ) \\).
c. \\( q ^ { prime } \\) is plotted at \\( ( - 4 , - 4 ) \\).
d. \\( q \\) and \\( q ^ { prime } \\) are in the same quadrant.
e. \\( p ^ { prime } \\) and \\( p \\) are in the same quadrant.
- which transformation or sequence of transformations maps \\( \triangle a b c \\) to \\( \triangle a ^ { prime } b ^ { prime } c ^ { prime } \\) ?
(a) a translation 5 units left
(b) a reflection across \\( x = 0 \\), then a translation 5 units left
(c) a reflection across \\( y = 0 \\), then a translation 5 units left
(d) a rotation \\( 90 ^ { \circ } \\) about the origin
- point \\( p ^ { prime } ( 5 , - 4 ) \\) is the image of point \\( p ( 2,3 ) \\) under a translation. select the image of \\( ( 6 , - 2 ) \\) under the same translation.
(a) \\( ( 7 , - 1 ) \\)
(b) \\( ( 13 , - 3 ) \\)
(c) \\( ( 9 , - 9 ) \\)
(d) \\( ( 3,5 ) \\)
- given point \\( a \\) is not on line \\( m \\), suppose \\( a \\) is reflected across line \\( m \\). which of the following is true?
(a) \\( overline { a a ^ { prime } } \\) is the bisector of line \\( m \\).
(b) line \\( m \\) is the perpendicular bisector of \\( overline { a a ^ { prime } } \\).
(c) line \\( m \\) is parallel to \\( overline { a a ^ { prime } } \\).
(d) \\( a = a ^ { prime } \\)
Step1: Analyze problem 1
- Translation and reflection: These are rigid transformations. Rigid transformations preserve side - lengths and angle - measures.
- For option A: Since \(ST = 4.3\mathrm{cm}\) and rigid transformations preserve side - lengths, \(R'S'=ST = 4.3\mathrm{cm}\).
- For option B: \(\angle R\) and \(\angle R'\) are corresponding angles. Rigid transformations preserve angle - measures, so \(\angle R\cong\angle R'\).
- For option C: \(m\angle T=m\angle T' = 71^{\circ}\) because rigid transformations preserve angle - measures.
- For option D: \(\overline{ST}\cong\overline{S'T'}\), not \(\overline{ST}\cong\overline{T'S'}\).
- For option E: Since rigid transformations preserve side - lengths, \(RT = R'T'\).
Step2: Analyze problem 2
- Reflection across \(x = 0\) (y - axis): The rule for reflection across the \(y\) - axis is \((x,y)\to(-x,y)\). For the point \(T(-2,5)\), after reflection across \(x = 0\), the point becomes \((2,5)\).
- Reflection across \(y = 0\) (x - axis): The rule for reflection across the \(x\) - axis is \((x,y)\to(x, - y)\). After reflection of \((2,5)\) across \(y = 0\), the point \(T'\) is \((2,-5)\).
Step3: Analyze problem 3
- Reflection across \(x=-1\):
- For option A: Reflection is a rigid transformation, so \(\overline{PQ}\cong\overline{P'Q'}\).
- For option B and C: The distance between a point \((x,y)\) and the line \(x = a\) is \(|x - a|\). For point \(Q(2,4)\), the distance from \(x=-1\) is \(|2-(-1)|=3\). The \(x\) - coordinate of \(Q'\) is \(-1-3=-4\), and the \(y\) - coordinate remains the same. So \(Q'(-4,4)\).
- For option D: \(Q(2,4)\) is in the first quadrant and \(Q'(-4,4)\) is in the second quadrant.
- For option E: \(P(-1,-3)\) (assuming from the graph), after reflection across \(x=-1\), \(P'(-1,-3)\) (since \(P\) is on the line \(x = - 1\)), so \(P\) and \(P'\) are in the same quadrant.
Step4: Analyze problem 4
- For option A: A translation 5 units left:
- For point \(A(5,5)\), \(A'(0,5)
eq A'(0, - 5)\).
- For option B:
- Reflection across \(x = 0\) (y - axis): The rule is \((x,y)\to(-x,y)\). For \(A(5,5)\to(-5,5)\), \(B(1,3)\to(-1,3)\), \(C(2,1)\to(-2,1)\).
- Translation 5 units left: The rule is \((x,y)\to(x - 5,y)\). For \((-5,5)\to(0,5)
eq(0,-5)\).
- For option C:
- Reflection across \(y = 0\) (x - axis): The rule is \((x,y)\to(x,-y)\). For \(A(5,5)\to(5,-5)\), \(B(1,3)\to(1,-3)\), \(C(2,1)\to(2,-1)\).
- Translation 5 units left: The rule is \((x,y)\to(x - 5,y)\). For \((5,-5)\to(0,-5)\), \((1,-3)\to(-4,-3)\), \((2,-1)\to(-3,-1)\).
- For option D:
- Rotation \(90^{\circ}\) about the origin: The rule for a \(90^{\circ}\) clockwise rotation about the origin is \((x,y)\to(y,-x)\). For \(A(5,5)\to(5,-5)
eq(0,-5)\).
Step5: Analyze problem 5
- Find the translation vector:
- If \(P(2,3)\) is translated to \(P'(5,-4)\), the translation vector \((a,b)\) is found by \((x + a,y + b)\). So \(a=5 - 2=3\) and \(b=-4 - 3=-7\).
- Apply the translation to \((6,-2)\): Using the rule \((x,y)\to(x + 3,y-7)\), we get \((6 + 3,-2-7)=(9,-9)\).
Step6: Analyze problem 6
- Reflection properties:
- When a point \(A\) is reflected across a line \(m\) (where \(A
otin m\)), the line \(m\) is the perpendicular bisector of the segment \(\overline{AA'}\).
- For option A: \(\overline{AA'}\) is perpendicular to line \(m\) (not a bisector of \(m\)).
- For option C: Line \(m\) is perpendicular to \(\overline{AA'}\), not pa…
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