Question

suppose an object is traveling in a circle of radius 10 m. if the object has a period of 6 s, what is its orbital speed (in m/s)?
a 5.2
b 10.5
c 20.9
d 62.8

Explanation:

Step1: Calculate the circumference of the circle

The formula for the circumference of a circle is \(C = 2\pi r\). Given \(r = 10\space m\), then \(C=2\times\pi\times10 = 20\pi\space m\).

Step2: Use the formula for orbital speed

Orbital speed \(v=\frac{C}{T}\), where \(T\) is the period. Given \(T = 6\space s\) and \(C = 20\pi\space m\), then \(v=\frac{20\pi}{6}\). Substituting \(\pi\approx3.14\), we get \(v=\frac{20\times3.14}{6}=\frac{62.8}{6}\approx10.5\space m/s\).

Answer:

B. 10.5