Question

1. subtract the following expressions:

$(2r^2 + r - 1) - (3r^2 + 4r - 5)$
choose the three terms that will be in the
resulting expression.
$square$ $-r^2$
$square$ $5r^2$
$square$ $-3r$
$square$ $5r$
$square$ $-6$
$square$ $4$
clear all

Explanation:

Step1: Distribute the negative sign

We have \((2r^{2}+r - 1)-(3r^{2}+4r - 5)=2r^{2}+r - 1-3r^{2}-4r + 5\)

Step2: Combine like - terms for \(r^{2}\) terms

For the \(r^{2}\) terms: \(2r^{2}-3r^{2}=-r^{2}\)

Step3: Combine like - terms for \(r\) terms

For the \(r\) terms: \(r-4r=-3r\)

Step4: Combine like - terms for constant terms

For the constant terms: \(- 1 + 5=4\)

Answer:

The three terms in the resulting expression are \(-r^{2}\), \(-3r\) and \(4\). So the correct options are:

• \(\square\) \(-r^{2}\) (checked)
• \(\square\) \(-3r\) (checked)
• \(\square\) \(4\) (checked)