Question

a student connects four aa batteries (each battery is 1.5 v) in series to light up a light bulb. the circuit has a resistance of 60ω. how much current flows through the circuit? 1 a 75 a 0.10 a 600 a

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \(V = IR\), where \(V\) is voltage, \(I\) is current, and \(R\) is resistance. We need to solve for \(I\), so the formula becomes \(I=\frac{V}{R}\).

Step2: Substitute the given values

Given \(V = 1.5\space V\) and \(R = 52\space\Omega\). Substitute into \(I=\frac{V}{R}\), we get \(I=\frac{1.5}{52}\).

Step3: Calculate the current

\(I=\frac{1.5}{52}\approx0.0288\approx0.03\space A\)

Answer:

0.03 A