Question

a student collects information about the mass of and force acting on different boxes and records the information in the table. which statement accurately compares the acceleration of the boxes? select two correct answers.

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. We can rearrange this formula to find the acceleration \(a=\frac{F}{m}\).

Step2: Calculate acceleration for each box

• Box 1: \(F = 5N\), \(m = 1kg\). Using \(a=\frac{F}{m}\), we get \(a_1=\frac{5}{1}=5m/s^{2}\).
• Box 2: \(F = 50N\), \(m = 1kg\). Using \(a=\frac{F}{m}\), we get \(a_2=\frac{50}{1}=50m/s^{2}\).
• Box 3: \(F = 5N\), \(m = 10kg\). Using \(a=\frac{F}{m}\), we get \(a_3=\frac{5}{10}=0.5m/s^{2}\).
• Box 4: \(F = 50N\), \(m = 10kg\). Using \(a=\frac{F}{m}\), we get \(a_4=\frac{50}{10}=5m/s^{2}\).

Answer:

Box 1 and Box 4 have the same acceleration (\(5m/s^{2}\)), and Box 2 has a greater acceleration than Box 3 (\(50m/s^{2}>0.5m/s^{2}\)).