Question

a string of holiday lights is wired in a series circuit. if one bulb burns out, all the other bulbs go out as well. why does this happen? a. the battery stops producing energy. b. the open spot in the circuit stops the current from flowing. c. the other bulbs require more energy than the battery can supply. d. the current flows backward through the wire.

Explanation:

In a series - circuit, all components are connected end - to - end in a single path for the current. When one bulb burns out, it creates an open circuit. In an open circuit, there is a break in the path, and the current cannot flow through the circuit. This causes all the other bulbs to go out as well.

Answer:

B. The open spot in the circuit stops the current from flowing.