Question

step 3: apply the scaling factor to the empirical formula. the scale factor is 5 and the empirical formula is ch₂o. what is the molecular formula? c? h o enter the subscript that goes in the green box. c subscript submit

Explanation:

Step1: Recall the relationship between molecular and empirical formula

The molecular formula is \(n\) times the empirical formula, where \(n\) is the scaling factor. For the element \(C\) in the empirical formula \(CH_2O\), its sub - script is \(1\).

Step2: Calculate the sub - script for \(C\) in the molecular formula

Since \(n = 5\) (scaling factor) and the sub - script of \(C\) in the empirical formula is \(1\), we use the formula \(sub - script_{molecular}=n\times sub - script_{empirical}\). So, \(sub - script_{molecular}(C)=5\times1\)

Answer:

\(5\)