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Question
step 3: apply the scaling factor to the empirical formula. the scale factor is 5 and the empirical formula is ch₂o. what is the molecular formula? c₅h₁₀o? enter the subscript that goes in the green box.
Step1: Analyze the empirical formula
The empirical formula is \(CH_2O\), which has 1 oxygen atom.
Step2: Apply the scaling factor
The scaling factor is 5. Multiply the number of each atom in the empirical formula by the scaling factor. For oxygen: \(1\times5 = 5\)
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