Question

square roots
√81 = ?
betweens
1&2 2&3 3&4 4&5 5&6 6&7 7&8 8&9 9&10
0 1 2 3 4 5 6 7 8 9 10 11

Explanation:

Step1: Recall square root definition

The square root of a number \( x \), denoted \( \sqrt{x} \), is a value \( y \) such that \( y^2 = x \).

Step2: Find \( y \) where \( y^2 = 81 \)

We know that \( 9 \times 9 = 81 \) (or \( 9^2 = 81 \)) and also \( (-9)^2 = 81 \), but for the principal (non - negative) square root, we consider the positive value. So \( \sqrt{81}=9 \).

Answer:

9