Question

square roots
√32 = ?
betweens
1&2 2&3 3&4 4&5 5&6 6&7 7&8 8&9 9&10
0 1 2 3 4 5 6 7 8 9 10 11

Explanation:

Step1: Recall square numbers

We know that \(5^2 = 25\) and \(6^2 = 36\).

Step2: Compare with 32

Since \(25<32<36\), taking square roots, we get \(\sqrt{25}<\sqrt{32}<\sqrt{36}\), which simplifies to \(5 < \sqrt{32}< 6\). So \(\sqrt{32}\) is between 5 and 6.

Answer:

The square root of 32 (\(\sqrt{32}\)) is between 5 and 6, so the correct interval is "5&6".