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résous chacune des équ a) $x + 2x + 4,1 = 14,6$

Question

résous chacune des équ
a) $x + 2x + 4,1 = 14,6$

Explanation:

Step1: Combine like terms

First, combine the \(x\) terms on the left - hand side of the equation \(x + 2x+4.1 = 14.6\). We know that \(x+2x=(1 + 2)x=3x\), so the equation becomes \(3x + 4.1=14.6\).

Step2: Isolate the term with x

Subtract \(4.1\) from both sides of the equation to isolate the term with \(x\). Using the subtraction property of equality, we have \(3x+4.1 - 4.1=14.6 - 4.1\). Simplifying both sides, we get \(3x = 10.5\).

Step3: Solve for x

Divide both sides of the equation \(3x = 10.5\) by \(3\) to solve for \(x\). Using the division property of equality, \(\frac{3x}{3}=\frac{10.5}{3}\), which gives \(x = 3.5\).

Answer:

\(x = 3.5\)