Question

solve for f.
$f - 18 \leq -8$ or $\frac{f - 11}{4} \geq 0$
write your answer as a compound inequality with integers.

Explanation:

Step1: Solve \( f - 18 \leq -8 \)

Add 18 to both sides of the inequality.
\( f - 18 + 18 \leq -8 + 18 \)
\( f \leq 10 \)

Step2: Solve \( \frac{f - 11}{4} \geq 0 \)

Multiply both sides by 4 (since 4 is positive, the inequality sign remains the same).
\( \frac{f - 11}{4} \times 4 \geq 0 \times 4 \)
\( f - 11 \geq 0 \)
Then add 11 to both sides.
\( f - 11 + 11 \geq 0 + 11 \)
\( f \geq 11 \)

Answer:

\( f \leq 10 \) or \( f \geq 11 \)