Question

solve for x, where x is a real number.
\\(\sqrt{x} = -6\\)
if there is more than one solution, separate them with commas.
if there is no solution, click on
o solution\.
\\(x = \square\\)

Explanation:

Step1: Recall square root definition

The principal square root function \( \sqrt{x} \) (for real \( x \)) is defined such that \( \sqrt{x} \geq 0 \) when \( x \geq 0 \), and is not a real number when \( x < 0 \).

Step2: Analyze the equation \( \sqrt{x} = -6 \)

The left - hand side \( \sqrt{x} \) (for real \( x \)) must be non - negative (i.e., \( \sqrt{x}\geq0 \) for \( x\geq0 \)), but the right - hand side is \( - 6 \), which is negative. There is no real number \( x \) such that the square root of \( x \) is negative.

Answer:

No solution